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3x^2-65x-750=0
a = 3; b = -65; c = -750;
Δ = b2-4ac
Δ = -652-4·3·(-750)
Δ = 13225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{13225}=115$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-115}{2*3}=\frac{-50}{6} =-8+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+115}{2*3}=\frac{180}{6} =30 $
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